Dracula vs Italian Popular Tales
Both counted from their full texts, the same way, on the same day.
493words between them — 2 min of it
Dracula is longer — 160,686 words against 160,193 for Italian Popular Tales, a difference of 493 words or about 2 min of extra reading. Dracula is the harder read, at grade 7.5 against 6.1.
SOURCE·Project Gutenberg full texts·both editions counted the same way·REVIEWED JUL 2026
Side by side
| Dracula | Italian Popular Tales | |
|---|---|---|
| Author | Stoker, Bram | Crane, Thomas Frederick |
| Words | 160,686 | 160,193 |
| Reading time at 250 wpm | 10h 43m | 10h 41m |
| Unique words | 10,262 | 9,103 |
| Sentences | 7,804 | 10,072 |
| Average sentence length | 20.6 words | 15.9 words |
| Reading grade | 7.5 | 6.1 |
| Reading ease | 77.7 | 79.5 |
| Long words | 5.5% | 6.5% |
Highlighted cells are the larger figure — except reading ease, where higher means easier.
SOURCE·Project Gutenberg full texts·both editions, same counting rule·REVIEWED JUL 2026
How this is worked out
- Both texts are counted the same way, from the same source, with Gutenberg's header and licence footer struck first.
- The gap is stated in words and then in time at 250 words a minute — the rate is printed because a duration without one cannot be checked.
- Difficulty is compared on Flesch–Kincaid grade, which reads sentence and word length only. It cannot see irony or dialect, so treat it as a measure of surface, not of effort.
gap = |160,686 − 160,193| = 493 words 493 ÷ 250 wpm = 2 min of extra reading
The second question
Which is longer, Dracula or Italian Popular Tales?
Dracula is longer — 160,686 words against 160,193 for Italian Popular Tales, a difference of 493 words or about 2 min of extra reading. Dracula is the harder read, at grade 7.5 against 6.1.
Colophon
Both figures computed from Project Gutenberg plain-text editions — ebook no. 45839 and no. 23634 — and from no other source. Neither book’s text is set on this site.
SOURCE·Project Gutenberg full texts·US public domain·REVIEWED JUL 2026
Word counts and reading levels are computed from a specific public-domain edition and will differ from other editions and from other counting methods — see the method page.